Two integers from "Big Date" produce a rational quotient, but not immediately obvious: 11,427,680,865,484,800/948,109,639,680 where the denominator is the famous Jarvis No. (see: www.afjarvis.staff.shef.ac.uk/sudoku/ed44.html). The answer is 12,053.1216931. Fortran has a remainder out to 12 digits. My 1st thought was the ans. might be irrational (transcendental. that is), but my ancient, 21-year old HP 48GX calculator gave the correct result, confirming rationality. Also, I did find one correct web calculator, but most don't come close. There is a greatest common divisor, namely 5,016,453,120, which reduces the fraction to much lower terms: 2,278,040/189 = 12,053.1216931.
Best regards, Bearcat
Comment
Two integers from "Big Date" produce a rational quotient, but not immediately obvious: 11,427,680,865,484,800/948,109,639,680 where the denominator is the famous Jarvis No. (see: www.afjarvis.staff.shef.ac.uk/sudoku/ed44.html). The answer is 12,053.1216931. Fortran has a remainder out to 12 digits. My 1st thought was the ans. might be irrational (transcendental. that is), but my ancient, 21-year old HP 48GX calculator gave the correct result, confirming rationality. Also, I did find one correct web calculator, but most don't come close. There is a greatest common divisor, namely 5,016,453,120, which reduces the fraction to much lower terms: 2,278,040/189 = 12,053.1216931.
Best regards, Bearcat